Integrand size = 15, antiderivative size = 79 \[ \int \frac {(2+b x)^{5/2}}{x^{3/2}} \, dx=\frac {15}{2} b \sqrt {x} \sqrt {2+b x}+\frac {5}{2} b \sqrt {x} (2+b x)^{3/2}-\frac {2 (2+b x)^{5/2}}{\sqrt {x}}+15 \sqrt {b} \text {arcsinh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right ) \]
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Time = 0.01 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {49, 52, 56, 221} \[ \int \frac {(2+b x)^{5/2}}{x^{3/2}} \, dx=15 \sqrt {b} \text {arcsinh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right )-\frac {2 (b x+2)^{5/2}}{\sqrt {x}}+\frac {5}{2} b \sqrt {x} (b x+2)^{3/2}+\frac {15}{2} b \sqrt {x} \sqrt {b x+2} \]
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Rule 49
Rule 52
Rule 56
Rule 221
Rubi steps \begin{align*} \text {integral}& = -\frac {2 (2+b x)^{5/2}}{\sqrt {x}}+(5 b) \int \frac {(2+b x)^{3/2}}{\sqrt {x}} \, dx \\ & = \frac {5}{2} b \sqrt {x} (2+b x)^{3/2}-\frac {2 (2+b x)^{5/2}}{\sqrt {x}}+\frac {1}{2} (15 b) \int \frac {\sqrt {2+b x}}{\sqrt {x}} \, dx \\ & = \frac {15}{2} b \sqrt {x} \sqrt {2+b x}+\frac {5}{2} b \sqrt {x} (2+b x)^{3/2}-\frac {2 (2+b x)^{5/2}}{\sqrt {x}}+\frac {1}{2} (15 b) \int \frac {1}{\sqrt {x} \sqrt {2+b x}} \, dx \\ & = \frac {15}{2} b \sqrt {x} \sqrt {2+b x}+\frac {5}{2} b \sqrt {x} (2+b x)^{3/2}-\frac {2 (2+b x)^{5/2}}{\sqrt {x}}+(15 b) \text {Subst}\left (\int \frac {1}{\sqrt {2+b x^2}} \, dx,x,\sqrt {x}\right ) \\ & = \frac {15}{2} b \sqrt {x} \sqrt {2+b x}+\frac {5}{2} b \sqrt {x} (2+b x)^{3/2}-\frac {2 (2+b x)^{5/2}}{\sqrt {x}}+15 \sqrt {b} \sinh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right ) \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.89 \[ \int \frac {(2+b x)^{5/2}}{x^{3/2}} \, dx=\frac {\sqrt {2+b x} \left (-16+9 b x+b^2 x^2\right )}{2 \sqrt {x}}-30 \sqrt {b} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}-\sqrt {2+b x}}\right ) \]
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Time = 0.08 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.80
method | result | size |
meijerg | \(-\frac {15 \sqrt {b}\, \left (\frac {16 \sqrt {\pi }\, \sqrt {2}\, \left (-\frac {1}{16} b^{2} x^{2}-\frac {9}{16} b x +1\right ) \sqrt {\frac {b x}{2}+1}}{15 \sqrt {x}\, \sqrt {b}}-2 \sqrt {\pi }\, \operatorname {arcsinh}\left (\frac {\sqrt {b}\, \sqrt {x}\, \sqrt {2}}{2}\right )\right )}{2 \sqrt {\pi }}\) | \(63\) |
risch | \(\frac {b^{3} x^{3}+11 b^{2} x^{2}+2 b x -32}{2 \sqrt {x}\, \sqrt {b x +2}}+\frac {15 \sqrt {b}\, \ln \left (\frac {b x +1}{\sqrt {b}}+\sqrt {b \,x^{2}+2 x}\right ) \sqrt {x \left (b x +2\right )}}{2 \sqrt {x}\, \sqrt {b x +2}}\) | \(81\) |
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Time = 0.23 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.47 \[ \int \frac {(2+b x)^{5/2}}{x^{3/2}} \, dx=\left [\frac {15 \, \sqrt {b} x \log \left (b x + \sqrt {b x + 2} \sqrt {b} \sqrt {x} + 1\right ) + {\left (b^{2} x^{2} + 9 \, b x - 16\right )} \sqrt {b x + 2} \sqrt {x}}{2 \, x}, -\frac {30 \, \sqrt {-b} x \arctan \left (\frac {\sqrt {b x + 2} \sqrt {-b}}{b \sqrt {x}}\right ) - {\left (b^{2} x^{2} + 9 \, b x - 16\right )} \sqrt {b x + 2} \sqrt {x}}{2 \, x}\right ] \]
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Time = 4.71 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.19 \[ \int \frac {(2+b x)^{5/2}}{x^{3/2}} \, dx=15 \sqrt {b} \operatorname {asinh}{\left (\frac {\sqrt {2} \sqrt {b} \sqrt {x}}{2} \right )} + \frac {b^{3} x^{\frac {5}{2}}}{2 \sqrt {b x + 2}} + \frac {11 b^{2} x^{\frac {3}{2}}}{2 \sqrt {b x + 2}} + \frac {b \sqrt {x}}{\sqrt {b x + 2}} - \frac {16}{\sqrt {x} \sqrt {b x + 2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 113 vs. \(2 (56) = 112\).
Time = 0.29 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.43 \[ \int \frac {(2+b x)^{5/2}}{x^{3/2}} \, dx=-\frac {15}{2} \, \sqrt {b} \log \left (-\frac {\sqrt {b} - \frac {\sqrt {b x + 2}}{\sqrt {x}}}{\sqrt {b} + \frac {\sqrt {b x + 2}}{\sqrt {x}}}\right ) - \frac {\frac {7 \, \sqrt {b x + 2} b^{2}}{\sqrt {x}} - \frac {9 \, {\left (b x + 2\right )}^{\frac {3}{2}} b}{x^{\frac {3}{2}}}}{b^{2} - \frac {2 \, {\left (b x + 2\right )} b}{x} + \frac {{\left (b x + 2\right )}^{2}}{x^{2}}} - \frac {8 \, \sqrt {b x + 2}}{\sqrt {x}} \]
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Time = 5.89 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.97 \[ \int \frac {(2+b x)^{5/2}}{x^{3/2}} \, dx=\frac {{\left (\frac {{\left ({\left (b x + 7\right )} {\left (b x + 2\right )} - 30\right )} \sqrt {b x + 2}}{\sqrt {{\left (b x + 2\right )} b - 2 \, b}} - \frac {30 \, \log \left ({\left | -\sqrt {b x + 2} \sqrt {b} + \sqrt {{\left (b x + 2\right )} b - 2 \, b} \right |}\right )}{\sqrt {b}}\right )} b^{2}}{2 \, {\left | b \right |}} \]
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Timed out. \[ \int \frac {(2+b x)^{5/2}}{x^{3/2}} \, dx=\int \frac {{\left (b\,x+2\right )}^{5/2}}{x^{3/2}} \,d x \]
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